\(A=\frac{5x^2-40x+60}{\left(x-2\right)\left(x-6\right)}=\frac{5\left(x^2-8x+12\right)}{\left(x-2\right)\left(x-6\right)}\)
\(\frac{5\left(x^2-2x-6x+12\right)}{\left(x-2\right)\left(x-6\right)}=\frac{5\left[x\left(x-2\right)-6\left(x-2\right)\right]}{\left(x-2\right)\left(x-6\right)}\)
\(=\frac{5\left(x-2\right)\left(x-6\right)}{\left(x-2\right)\left(x-6\right)}=5\)