b) - Đặt CTHH tổng quát của oxit gồm 3 kim loại đó là \(X_2O_n\)
\(2X+\dfrac{n}{2}O_2\) ---to----> \(X_2O_n\) (1)
- Theo PTHH(1): nX = 2.\(n_{X_2O_n}\)
=> \(\dfrac{13,1}{X}=\dfrac{2.20,3}{2X+16n}\)
=> n = \(\dfrac{9}{131}X\)
\(X_2O_n+2nHCl\) ------> \(2XCl_n+\dfrac{n}{2}H_2O\) (2)
- Theo PTHH (2): \(n_{XCln}=2n_{X2On}\)
\(\Leftrightarrow\dfrac{m_{XCln}}{X+35,5n}=2.\dfrac{13,1}{2X}\)
\(\Leftrightarrow m_{XCln}=2.\dfrac{13,1}{2X}.\left(X+35,5n\right)\)
\(\Rightarrow m_{XCln}=2.\dfrac{13,1}{2X}.\left(X+35,5n\right)\)
Mà \(n=\dfrac{9}{131}X\)
=> mXCln = 45,05 gam