Bt1:
\(\dfrac{PTK_X}{PTK_{O_2}}=\dfrac{7}{8}\\ PTK_{O_2}=32\left(đvC\right)\)
\(\Rightarrow PTK_X=\dfrac{7}{8}.32=28\left(đvC\right)\)
\(\Rightarrow M_X=28\left(\dfrac{g}{mol}\right)\)
\(\Rightarrow m_C=\%C.M_X=85,71\%.28=24\left(g\right)\\ m_H=m_X-m_C=28-24=4\left(g\right)\)
\(\Rightarrow n_C=\dfrac{m}{M}=\dfrac{24}{12}=2\left(mol\right)\\ n_H=\dfrac{m}{M}=\dfrac{4}{1}=4\left(\dfrac{g}{mol}\right)\)
\(CTHH:C_2H_4\)
Bt2:
\(\dfrac{PTK_A}{PTK_{O_2}}=5,625\\ PTK_{O_2}=32\left(đvC\right)\\ \Rightarrow PTK_A=5,625.32=180\left(đvC\right)\)
\(\Rightarrow M_A=180\left(đvC\right)\)
\(\Rightarrow m_C=\%C.M_A=40\%.180=72\left(g\right)\\ m_H=\%H.M_A=6,67\%.180=12\left(g\right)\\ m_O=m_A-m_C-m_H=180-72-12=96\left(g\right)\)
\(\Rightarrow n_C=\dfrac{m}{M}=\dfrac{72}{12}=6\left(mol\right)\\ n_H=\dfrac{m}{M}=\dfrac{12}{1}=12\left(mol\right)\\ n_O=\dfrac{m}{M}=\dfrac{96}{16}=6\left(mol\right)\)
\(CTHH:C_6H_{12}O_6\)
