\(\frac{2x}{5}=\frac{3y}{8}=\frac{5t}{3}\)và \(x-2y+3t=-279\)
Thgeo bài ra ta cs
\(\frac{x}{10}=\frac{y}{24}=\frac{t}{15}\)và \(x-2y+3t=-279\)
ADTC dãy tỉ số bằng nhau ta cs
\(\frac{x}{10}=\frac{y}{24}=\frac{t}{15}=\frac{x-2y+3t}{10-2.24+3.15}=-\frac{279}{7}\)
\(\Rightarrow\hept{\begin{cases}\frac{x}{10}=-\frac{279}{7}\\\frac{y}{25}=-\frac{279}{7}\\\frac{t}{15}=-\frac{279}{7}\end{cases}\Rightarrow\hept{\begin{cases}x=-\frac{2790}{7}\\y=-\frac{69750}{7}\\t=\frac{-1046250}{7}\end{cases}}}\)