\(a+a.\frac{3}{2}+a:\frac{2}{7}=252\)
=>\(a+a.\frac{3}{2}+a.\frac{7}{2}=252\)
=>\(a.\left(1+\frac{3}{2}+\frac{7}{2}\right)=252\)
=>\(a.\left(1+5\right)=252\)
=>\(a.6=252\)
=>\(a=42\)
Vậy \(a=42\)
A+Ax3/2+A:2/7=252
A+Ax3/2+Ax7/2=252
Ax(1+3/2+7/2)=252
Ax6=252
A=42
HT