Ta có: \(\frac{2-x}{4}=\frac{3x-1}{3}\)
\(\Leftrightarrow\left(2-x\right).3=\left(3x-1\right).4\)
\(\Leftrightarrow6-3x=12x-4\)
\(\Leftrightarrow-3x-12x=-4-6\)
\(\Leftrightarrow-15x=-10\)
\(\Leftrightarrow x=\frac{2}{3}\)
Vậy ...
\(\frac{2-x}{4}=\frac{3x-1}{3}\)
\(3.\left(2-x\right)=4.\left(3x-1\right)\)
\(6-3x=12x-4\)
\(-3x-12x=-4-6\)
\(-15x=-10\)
\(x=\frac{2}{3}\)
Vậy \(x=\frac{2}{3}\)
2 - x/4 = 3x - 1/3
<=> (2 - x).3 = 4.(3x - 1)
<=> 6x - 3x = 12x - 4
<=> -3x = 12x - 4 - 6
<=> -3x = 12x - 10
<=> -3x - 12x = -10
<=> -15x = -10
<=> x = 2/3
=> x = 2/3
Theo đề bài ta có:
\(\left(2-x\right).3=4.\left(3x-1\right)\)
\(\Rightarrow6-3x=12x-4\)
\(\Rightarrow10=15x\)
\(\Rightarrow x=\frac{10}{15}=\frac{2}{3}\)
