a, Vì 4 < 16 < 64 < 256 (Khi lập TLT luôn lấy số lớn nhất nhân số bé nhất trước rồi mới đến 2 số còn lại)
Ta có: 256.4 = 1024
64.16 = 1024
=> 256.4 = 64.16
\(\Rightarrow\frac{256}{64}=\frac{16}{4};\)\(\frac{256}{16}=\frac{64}{4};\)\(\frac{4}{64}=\frac{16}{256};\)\(\frac{4}{16}=\frac{64}{256}\)
lap ca ti so bang nhau trong cac ti so sau roi lap cac ti le thuc
a)1/3; 2,5/5,5; 4:12; -7/4
b) 4/9; 18/42 ; -2/-4,5; 21:49; 5/9
2lap tac ca cac ti le thuc co duoc tu cac so sau 2,4;4,0,2,1 5,6
kiem tra xem cac ti so sau co lap dc ti le thuc hay ko neu duoc thi lap tat ca
\(\frac{1}{5}\) và 25: 125
có thể lập dc ti le thuc tu cac so sau day ko? neu lap dc hay viet tat ca cac ti le thuc do
a)1,75; 20; 34 ;29,75
b)1,3; 3,2; 2,1; 5,4
đung lam tắt nha lam dung mk kick cho
Bà 18 : Thực hiện các phép tính sau = cách hợp lý nhất :
a) ( -40/51 . 0,32 . 17/20 ) : 64/75
b) -10/11 . 8/9 + 7/18 . 10/11
c) 3/14 : 1/28 - 13/21 : 1/28 + 29/42 : 1/28 - 8
d) \(-1\frac{5}{7}.15+\frac{2}{7}.\left(-15\right)+\left(-105\right).\left(\frac{2}{3}-\frac{4}{5}+\frac{1}{7}\right)\)
Tính giá trị biểu thức
\(1.A=\frac{1}{5}+\frac{3}{17}-\frac{4}{3}+\left(\frac{4}{5}-\frac{3}{17}+\frac{1}{3}\right)-\frac{1}{7}+\left[\frac{-14}{30}\right]\)
\(2.B=\left(\frac{5}{8}-\frac{4}{12}+\frac{3}{2}\right)-\left(\frac{5}{8}+\frac{9}{13}\right)-\left[\frac{-3}{2}\right]+\frac{7}{-15}\)
\(3.C=\frac{5}{18}+\frac{8}{19}-\frac{7}{21}+\left(\frac{-10}{36}+\frac{11}{19}+\frac{1}{3}\right)-\frac{5}{8}\)
\(4.D=\frac{1}{9}-\left[\frac{-5}{23}\right]-\left(\frac{-5}{23}+\frac{1}{9}+\frac{25}{7}\right)+\frac{50}{14}-\frac{7}{30}\)
\(5.E=\frac{1}{13}+\left(\frac{-5}{18}-\frac{1}{13}+\frac{12}{17}\right)+\left(\frac{12}{17}+\frac{5}{18}+\frac{7}{5}\right)\)
\(6.F=\frac{15}{14}-\left(\frac{17}{23}-\frac{80}{87}+\frac{5}{4}\right)+\left(\frac{12}{17}-\frac{15}{14}+\frac{1}{4}\right)\)
\(7.G=\frac{1}{25}-\frac{4}{27}+\left(\frac{-23}{27}+\frac{-1}{25}-\frac{5}{43}\right)+\frac{5}{43}-\frac{4}{7}\)
\(8.H=\frac{4}{15}-\frac{23}{28}-\left(\frac{-23}{28}+\frac{-11}{15}-\frac{29}{27}\right)-\frac{2}{27}\)
\(9.K=\frac{1}{16}-\frac{5}{21}+\left(\frac{-1}{16}+\frac{-3}{5}-\frac{-5}{21}\right)+\frac{-2}{5}+\frac{3}{4}\)
\(10.L=\frac{7}{12}+\frac{15}{14}-\left(\frac{14}{22}+\frac{-1}{14}+\frac{5}{21}\right)-\frac{-5}{21}+\frac{3}{5}\)
HAY LAP TAT CA CAC TI LE THUC TU BON TRONG NAM SO SAU
5,25,125,625,3125
Tu ti le thuc \(\frac{10x-12y}{3}=\frac{12y-15z}{4}=\frac{15z-10x}{5}\)
ta thu duoc ti le thuc ............
Hay lap cac ti le thuc tu cac so sau ( moi so chi duoc viet 1 lan ) :
3 ; 9 ; 27 ; 81 ; 243
a)A=\(\frac{16^3.3^{10}+120.6^9}{4^6.3^{12}+6^{11}}\) b)B=\(\frac{45}{19}-\left(\frac{1}{2}\left(\frac{1}{3}+\left(\frac{1}{4}\right)^{-1}\right)^-\right)^{-1}\) c)C=\(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^{10}.6^{19}-7.2^{29}.27^6}\)
d)D=\(\frac{2^{21}.3^5-4^6.81}{\left(2^2.3\right)^6+8^4.3^5}\) e) E=\(\left(6^9.2^{10}+12^{10}\right):\left(2^{19}.27^3+15.4^9.9^4\right)\)
f) F=\(\frac{3^6.45^4-15^{13}.5^{-9}}{27^4.24^3+45^6}\) g)G=\(\frac{\left(\frac{2}{5}\right)^7.5^7+\left(\frac{9}{4}\right)^3:\left(\frac{3}{16}\right)^3}{2^7.5^2+512}\) h)H=\(x+\frac{0,2-0,375+\frac{5}{11}}{-0,3+\frac{9}{16}-\frac{15}{22}}\)với x=-1/3
