Question

giúp mình bài 5 với ạ

Answer 1

Bài 5:

a: (2x^4-x^3-x^2+7x-4)/(x^2+x-1)

\(=\dfrac{2x^4+2x^3-2x^2-3x^3-3x^2+3x+4x^2+4x-4}{x^2+x-1}\)

\(=2x^2-3x+4\)

b: \(\dfrac{y}{2x^2-xy}+\dfrac{4x}{y^2-2xy}\)

\(=\dfrac{y}{x\left(2x-y\right)}+\dfrac{4x}{y\left(y-2x\right)}\)

\(=\dfrac{y^2-4x^2}{xy\left(2x-y\right)}=\dfrac{\left(y-2x\right)\left(y+2x\right)}{xy\left(2x-y\right)}=\dfrac{-2x-y}{xy}\)

c: \(=\dfrac{6\left(x+8\right)}{7\left(x-1\right)}\cdot\dfrac{\left(x-1\right)^2}{\left(x-8\right)\left(x+8\right)}=\dfrac{6\left(x-1\right)}{7\left(x-8\right)}\)