\(DK:-\frac{1}{3}\le x\le6\)
\(\Leftrightarrow\left(\sqrt{3x+1}-4\right)-\left(\sqrt{6-x}-1\text{ }\right)+\left(3x^2-15x\right)+\left(x-5\right)=0\)
\(\Leftrightarrow\frac{3x+1-16}{\sqrt{3x+1}+4}-\frac{6-x-1}{\sqrt{6-x}+1}+3x\left(x-5\right)+\left(x-5\right)=0\)
\(\Leftrightarrow\frac{3\left(x-5\right)}{\sqrt{3x+1}+4}+\frac{x-5}{\sqrt{6-x}+1}+3x\left(x-5\right)+\left(x-5\right)=0\)
\(\Leftrightarrow\left(x-5\right)\left(\frac{3}{\sqrt{3x+1}+4}+\frac{1}{\sqrt{6-x}+1}+3x+1\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x=5\left(n\right)\\\frac{3}{\sqrt{3x+1}+4}+\frac{1}{\sqrt{6-x}+1}+3x+1=0\left(l\right)\end{cases}}\)
Vay nghiem cua PT la \(x=5\)
