Question

Giải phương trình

\(\frac{x+2}{x+1}+\frac{3}{x-2}=\frac{3}{x^2-x-2}+1\)

Answer 1

0.5 nha bạn

Chúc bạn học tốt! :)

Answer 2

\(\frac{x+2}{x+1}+\frac{3}{x-2}=\frac{3}{x^2-x-x}+1\)

\(\Leftrightarrow\frac{\left(x+2\right)\left(x-2\right)}{\left(x+1\right)\left(x-2\right)}+\frac{3\left(x+1\right)}{\left(x-2\right)\left(x+1\right)}=\frac{3}{\left(x+1\right)\left(x-2\right)}+\frac{\left(x+1\right)\left(x-2\right)}{\left(x+1\right)\left(x-2\right)}\)

\(\Rightarrow x^2-4+3x+3=3+x^2-2x+x-2\)

\(\Leftrightarrow x^2-x^2+3x+2x-x=1+4-3\)

\(\Leftrightarrow4x=2\)

\(\Leftrightarrow x=\frac{1}{2}\)

Answer 3

\(ĐKXĐ:\hept{\begin{cases}x+1\ne0\\x-2\ne0\end{cases}}\)

\(\Leftrightarrow\hept{\begin{cases}x\ne-1\\x\ne2\end{cases}}\)

Vậy nên x=1/2 thỏa mãn ĐKXĐ nhé!