\(\frac{x+19}{3}+\frac{x+13}{5}=\frac{x+7}{7}+\frac{x+1}{9}\)
\(=>\frac{x+19}{3}+3+\frac{x+13}{5}+3=\frac{x+7}{7}+3+\frac{x+1}{9}+3\)
\(=>\frac{x+28}{3}+\frac{x+28}{5}=\frac{x+28}{7}+\frac{x+28}{9}\)
\(=>\frac{x+28}{3}+\frac{x+28}{5}-\frac{x+28}{7}-\frac{x+28}{9}=0\)
\(=>\left(x+28\right)\left(\frac{1}{3}+\frac{1}{5}-\frac{1}{7}-\frac{1}{9}\right)=0\)
Do :\(\frac{1}{3}+\frac{1}{5}-\frac{1}{7}-\frac{1}{9}\ne0\)
\(=>x+28=0\)
\(=>x=-28\)
Vậy nghiệm của phương trình trên là : -28
\(\frac{x+19}{3}+\frac{x+13}{5}=\frac{x+7}{7}+\frac{x+1}{9}\)
\(\Leftrightarrow\frac{x+19}{3}+3+\frac{x+13}{5}+3=\frac{x+7}{7}+3+\frac{x+1}{9}+3\)
\(\Leftrightarrow\frac{x+19+9}{3}+\frac{x+13+15}{5}=\frac{x+7+21}{7}+\frac{x+1+27}{9}\)
\(\Leftrightarrow\frac{x+28}{3}+\frac{x+28}{5}-\frac{x+28}{7}-\frac{x+28}{9}=0\)
\(\Leftrightarrow\left(x+28\right)\left(\frac{1}{3}+\frac{1}{5}+\frac{1}{7}+\frac{1}{9}\right)=0\)
\(\Leftrightarrow x=-28\)
Vậy \(x=-28\)
\(\frac{x+19}{3}+\frac{x+13}{5}=\frac{x+7}{7}+\frac{x+1}{9}\)
\(\Leftrightarrow\frac{x+19}{3}+3+\frac{x+13}{5}+3=\frac{x+7}{7}+3+\frac{x+1}{9}+3\)
\(\Leftrightarrow\left(x+28\right)\left(\frac{1}{3}+\frac{1}{5}\right)=\left(x+28\right)\left(\frac{1}{7}+\frac{1}{9}\right)\Rightarrow x+28=0\Leftrightarrow x=-28\)
