vì x là số nguyên dương và lớn nhất nên x=3
=> \(f\left(3\right)=2.3^2+30=2.9+20=18+30=48\)
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1. so x0 thoa man frac{5}{x}frac{x+1}{22}2. GTLN cua x thoa man 5^{left(x-2right)left(x+3right)}3. Gia tri x0 thoa man /x^2+50//-2x^2-1/4. Gia tri nguyen cua x thoa man left(3x-4right)^5^{left(3x-4right)^7}la x5. So gia tri cua x thoa man /x-2014/+/x-2015/06. Gia tri cua x de bieu thuc Afrac{x-3+5}{3-x+2}dat gia tri lon nhat la x
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1. so x>0 thoa man \(\frac{5}{x}=\frac{x+1}{22}\)
2. GTLN cua x thoa man \(5^{\left(x-2\right)\left(x+3\right)}\)
3. Gia tri x<0 thoa man /\(x^2+50\)/=/\(-2x^2\)-1/
4. Gia tri nguyen cua x thoa man \(\left(3x-4\right)^5\)=\(^{\left(3x-4\right)^7}\)la x=
5. So gia tri cua x thoa man /x-2014/+/x-2015/=0
6. Gia tri cua x de bieu thuc A=\(\frac{x-3+5}{3-x+2}\)dat gia tri lon nhat la x=
c1: Tap hop cac gia tri nguyen cua x thoa man \(\left(x+\frac{5}{4}\right)\left(x-\frac{19}{7}\right)\)<0
c2: Neu x,y la cac so nguyen thoa man 2xy+4y=6 thi y co the nhan nhung gia tri nam trong tap hop nao
c3: tim 3 so x,y,z biet x+y=8,x+z=10,y+z=12
C4: Gia tri cua x thoa man (x+3)^2=25 va x^3>0 la x=
Phan nguyen cua so huu ti x, ki hieu [x] la so nguyen lon nhat ko vuot qua x.
Hay tim phan nguyen cua: \(\left[\frac{5}{2}\right];\left[\frac{-3}{2}\right];\left[0,2\right]\)
cho xyz la cac so thuc thoa man 2x=3y=5z va /x-2y/=5 tinh gia tri lon nhat cua 3x-2z
\(\frac{7x+400y}{2014\left(x-3\right)^{2014}+1}\) tinh gia tri cua BT do biet x,y la cac so nguyen to thoa man : 17x+18y=124
cho x,y,z la cac so huu ti duong thoa man x+1/yz y +1/xz z+1/xy la cac so nguyen tim gia tri lon nhat cua bieu thuc A=x+y^2+z^3
tim gia tri m· cua C=\(\frac{x+2}{\left|x\right|}\)voi x la so nguyen
so cac so nguyen x thoa man \(\left(x^2+7x+2\right)chiahet\left(x+7\right)la\)
\(5^{\left(x+3\right)\left(2x-4\right)}=1\)
Tap hop cac gia tri x thoa man la ?