Ta có ;
\(\frac{x}{5}-\frac{5}{2}=-31\)
\(\Rightarrow\frac{2x-25}{10}=-31\)
\(\Rightarrow2x-25=-310\)
\(\Rightarrow2x=-285\)
\(\Rightarrow x=-\frac{285}{2}\)
\(\frac{x}{5}\)-\(\frac{5}{2}\)=-31
tìm x biết
\(\frac{1}{4}+\frac{2}{6}+\frac{3}{8}+\frac{4}{10}+\frac{5}{12}+...+\frac{30}{62}+\frac{31}{64}=2^x\)
tìm x biết
\(\frac{1}{4}.\frac{2}{6}.\frac{3}{8}.\frac{4}{10}.\frac{5}{12}....\frac{30}{62}.\frac{31}{64}=4^x\)
Tìm x, biết:
\(\frac{1}{4}\cdot\frac{2}{6}\cdot\frac{3}{8}\cdot\frac{4}{10}\cdot\frac{5}{12}\cdot.....\cdot\frac{30}{62}\cdot\frac{31}{64}=2^x\)
Tim x,y biet
a)\(\frac{x}{y}=\frac{4}{5},\frac{x+1,2}{y}=\frac{11}{15}\)
Tìm x biết rằng:
e) \(5^{x+2_{ }^{ }}\) = \(625\);
f) \(\left(x-1\right)^{x+2}\) = \(\left(x+1\right)^{x+4}\);
g) \(\left(2x-1\right)^3=-8\)
h) \(\frac{1}{4}\).\(\frac{2}{6}.\frac{3}{8}.\frac{4}{10}.\frac{5}{12}...\frac{30}{62}.\frac{31}{64}\) = \(2^x\)
1.Tim x : \(\frac{x-5}{\left|5-x\right|}=-1\)
30% cua x bang \(\frac{16}{5}\). Tim x
1) Giá trị \(x\in Z\) để \(\frac{x-5}{7-x}\) là số hữu tỉ dương. x = ?
2) Cặp số nguyên dương chẵn x; y thỏa mãn biểu thức \(\frac{x}{2}+\frac{3}{7}=\frac{5}{4}\). Vậy x = .... ; y = ....
3) Giá trị \(A=\frac{\frac{2}{5}+\frac{2}{7}-\frac{2}{11}}{\frac{3}{5}+\frac{3}{7}-\frac{3}{11}}+\frac{\frac{1}{4}-\frac{1}{5}+\frac{1}{7}}{\frac{3}{4}-\frac{3}{5}+\frac{3}{4}}\)
