Question

\(-\frac{32}{\left(-2\right)^n}=4\)

Answer 1

\(-\frac{32}{\left(-2\right)^n}=4\\ =>-\frac{32}{\left(-2\right)^n}=\frac{4}{1}\\ =>\left(-2\right)^n=8\\ =>n=3\)

Answer 2

\(-\frac{32}{\left(-2\right)^n}=4\Rightarrow\frac{\left(-2\right)^5}{\left(-2\right)^n}=\left(-2\right)^2\)

=> (-2)⁵:(-2)ⁿ=(-2)²

=> 5-n=2

=> n=3

Answer 3

\(\frac{-32}{\left(-2\right)^n}=4\Leftrightarrow\frac{-32}{-8}=4\Rightarrow\left(-2\right)^n=4\Rightarrow n=2\)

Answer 4

n=3

Answer 5

\(-\frac{32}{\left(-2\right)^n}=4\)

\(\Rightarrow\frac{\left(-2\right)^5}{\left(-2\right)^n}=\left(-2\right)^2\)

\(\Rightarrow\left(-2\right)^5:\left(-2\right)^n=\left(-2\right)^2\)

\(\Rightarrow5-n=2\)

\(\Rightarrow n=5-2\)

\(\Rightarrow n=3\)

Vậy : \(n=3\)