Question

\(\frac{1}{4}-\left(\frac{3}{4}+x\right)=2\)

Answer 1

\(\dfrac{1}{4}-\left(\dfrac{3}{4}+x\right)=2\)

\(\dfrac{3}{4}+x=\dfrac{1}{4}-2\)

\(\dfrac{3}{4}+x=\dfrac{-7}{4}\)

\(x=\dfrac{-7}{4}-\dfrac{3}{4}\)

\(x=\dfrac{-5}{2}\)

vậy \(x=\dfrac{-5}{2}\)

Answer 2

\(\dfrac{1}{4}-\left(\dfrac{3}{4}+x\right)=2\)

=>\(x+\dfrac{3}{4}=\dfrac{1}{4}-2=-\dfrac{7}{4}\)

=>\(x=-\dfrac{7}{4}-\dfrac{3}{4}=-\dfrac{10}{4}=-\dfrac{5}{2}\)