ta có : 1/1.2+1/2.3+1/3.4+1/4.5+....+1/49.50
= 1/1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+.....+1/49-1/50
=1/1-1/50
= 49/50
\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{49.50}\)
\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{49}-\frac{1}{50}\)
\(=\frac{1}{1}-\frac{1}{50}\)
\(=\frac{49}{50}\)
ta có : 1/1.2+1/2.3+1/3.4+1/4.5+....+1/49.50
= 1/1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+....+1/49-1/50
=1/1-1/50
=49/50
\(=1-\left(\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-...-\frac{1}{49}+\frac{1}{49}-\frac{1}{50}\right)\)
\(=1-\frac{1}{50}\)
\(=\frac{49}{50}\)
1/1.2+1/2.3+1/3.4+1/4.5+.......+1/49.50=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+.........+1/49-1/50=1-1/50=50/50-1/50=49/50
ta có : 1/1.2+1/2.3+1/3.4+1/4.5+....+1/49.50
= 1/1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+.....+1/49-1/50
=1/1-1/50
= 49/50
ta có : 1/1.2+1/2.3+1/3.4+1/4.5+....+1/49.50
= 1/1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+.....+1/49-1/50
=1/1-1/50
= 49/50
ta có : 1/1.2+1/2.3+1/3.4+1/4.5+....+1/49.50
= 1/1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+.....+1/49-1/50
=1/1-1/50
= 49/50
ta có : 1/1.2+1/2.3+1/3.4+1/4.5+....+1/49.50
= 1/1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+.....+1/49-1/50
=1/1-1/50
= 49/50