Question

\(\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+.........+\frac{1}{8.9.10}\) Tính đê các bác

Answer 1

Ta có:

\(\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+...+\frac{1}{8.9.10}\)

\(=\frac{1}{2}.\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+...+\frac{1}{8.9}-\frac{1}{9.10}\right)\)

\(=\frac{1}{2}.\left(\frac{1}{2}-\frac{1}{90}\right)\)

=\(\frac{11}{45}\)

Answer 2

=1/2.(1/1*2-1/2*3+1/2*3-1/3*4+...+1/8*9-1/9*10)

=1/2.(1/1*2-1/9*10)

=1/2.44/90

=22/90

nha

Answer 3

Nghị Hoàng Vũ sai rồi kìa. 1/2.(1/2-1/90) mà bằng 11/45 à