a, PT: \(4P+5O_2\underrightarrow{t^o}2P_2O_5\)
b, Ta có: \(n_{O_2}=\dfrac{4,48}{22,4}=0,2\left(mol\right)\)
Theo PT: \(n_P=\dfrac{4}{5}n_{O_2}=0,16\left(mol\right)\)
\(\Rightarrow m_P=0,16.31=4,96\left(g\right)\)
c, Theo PT: \(n_{P_2O_5}=\dfrac{2}{5}n_{O_2}=0,08\left(mol\right)\)
\(\Rightarrow m_{P_2O_5}=0,08.142=11,36\left(g\right)\)