Tính M = \(1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{100}}\)
Tính M = \(1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{100}}\)
chúng minh giá trị biểu thức sau ko phụ thuộc vào giá trị biến
a) (x-1)(x-2)(1+x+x2)(4+2x+x2)-x6+9x3
b) (\(\dfrac{1}{3}\)+2x)(4x2-\(\dfrac{2}{3}\)x+\(\dfrac{1}{9}\))-(2x-\(\dfrac{1}{3}\))(4x2+\(\dfrac{2}{3}\)x+\(\dfrac{1}{4}\))
c) (x-1)3-(x-1)(x2+x+1)-3(1-x)x
d) (x2-y2)(x2+xy+y2)(x2-xy+y2)+y6-x6
Mọi người giúp em vs ạ
1/ \(\dfrac{x-4}{3}+2x=\dfrac{4x-2}{6}\)
2/ \(\dfrac{5x-2}{5}-2=\dfrac{1-2x}{3}\)
3/ \(\dfrac{x-2}{2}-\dfrac{2}{3}=x-1\)
4/ \(\dfrac{2x-1}{3}+\dfrac{3x-2}{4}=\dfrac{4x-3}{5}\)
5/ \(\dfrac{x-3}{9}-\dfrac{x+2}{6}=\dfrac{x+4}{18}-\dfrac{1}{2}\)
1/ \(\dfrac{x+4}{4}+\dfrac{3x-7}{5}=\dfrac{7x+2}{20}\)
2/ \(\dfrac{x}{6}+\dfrac{1-3x}{9}=\dfrac{-x+1}{12}\)
3/ \(\dfrac{x-3}{3}-\dfrac{x+2}{12}=\dfrac{2x-1}{4}\)
4/ \(\dfrac{x-2}{4}-\dfrac{2x+3}{3}=\dfrac{x+6}{12}\)
5/ \(\dfrac{2x-1}{12}-\dfrac{3-x}{18}=\dfrac{-1}{36}\)
thực hiện phép tính
\(\dfrac{11x}{2x-3}+\dfrac{x-18}{2x-3}\)
\(\dfrac{2x+12}{4x^2-9}+\dfrac{2x+5}{4x-6}\)
\(\dfrac{x}{2x+1}+\dfrac{-1}{4x^2-1}+\dfrac{2-x}{2x-1}\)
giải các phương trinh sau
1/ \(\dfrac{4x-4}{3}-\dfrac{7-x}{5}\)
2/ \(\dfrac{3x-9}{5}=\dfrac{3-x}{2}\)
3/ \(\dfrac{2x-1}{5}-\dfrac{3-x}{3}=1\)
4/ \(\dfrac{x-5}{3}+\dfrac{3x+4}{2}=\dfrac{5x+2}{6}\)
5/ \(\dfrac{x-3}{2}+\dfrac{2x+3}{5}=\dfrac{2x+5}{10}\)
Tính:
a) \(\dfrac{x+1}{2x-6}+\dfrac{2x+3}{x^2+3x}\)
b) \(\dfrac{3}{2x+6}-\dfrac{x-6}{3x^2+6}\)
c) \(\dfrac{2x+6}{3x^2-x}:\dfrac{x^2+3x}{1-3x}\)
Cho biểu thức: P = \(\dfrac{2x-9}{x^2-5x+6}\) - \(\dfrac{x+3}{x-2}-\dfrac{2x+1}{3-x}\)
a) Rút gọn P
b) Tìm x để P nguyên
giải các phương trình sau
a, 3(x-1) -3=2(x+3)
b, \(\dfrac{x+4}{4}-\dfrac{x+3}{3}=\dfrac{x+6}{6}\)
c,\(\left(2x-1\right)^2-x^2=0\)
d,\(\dfrac{x}{x+3}-\dfrac{2x}{x-3}-\dfrac{3x}{9-x^2}=0\)
\(\dfrac{x}{x+3}-\dfrac{2x-1}{2x-6}=\dfrac{x+2}{x^2-9}\)