\(D=\frac{1006-\left(1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{2011}\right)}{\frac{2}{3}+\frac{4}{5}+...+\frac{2010}{2011}}\)
\(D=\frac{1006-\left(1+\frac{1}{3}+...+\frac{1}{2011}\right)}{1-\frac{1}{3}+1-\frac{1}{5}+...+1-\frac{1}{2011}}\)
\(D=\frac{1006-\left(1+\frac{1}{3}+...+\frac{1}{2011}\right)}{1006-\left(1+\frac{1}{3}+...+\frac{1}{2011}\right)}=1\)