Question

Chứng minh rằng: \(\frac{1}{100}\)+\(\frac{1}{1001}\)+............+\(\frac{1}{2000}\)> \(\frac{1}{2}\)

Answer 1

1/1000 hay 1/100 vậy

Answer 2

1/100 nha bạn

Answer 3

Có 1/100>1/2000

1/1001>1/2000

........

1/1999>1/2000

1/2000=1/2000

=>1/100+1/1001+.....+1/2000>1/2000+1/2000+....+1/2000

=>1/100+1/1001+.....+1/2000 > 1001/2000

Do 1001/2000>1/2

=>1/100+1/1001+.....+1/2000>1/2

Answer 4

\(\frac{1}{100}>\frac{1}{2000};\frac{1}{1001}>\frac{1}{2000};\frac{1}{1002}>\frac{1}{2000};...;\frac{1}{1999}>\frac{1}{2000}\)

=> \(\frac{1}{100}+\frac{1}{1001}+...+\frac{1}{2000}>\frac{1}{2000}+\frac{1}{2000}+...+\frac{1}{2000}=\frac{1001}{2000}>\frac{1000}{2000}=\frac{1}{2}\)

=> \(\frac{1}{100}+\frac{1}{1001}+...+\frac{1}{2000}>\frac{1}{2}\)