Đặt \(S=\dfrac{1}{100^2}+\dfrac{1}{101^2}+...+\dfrac{1}{199^2}\)
\(S< \dfrac{1}{99.100}+\dfrac{1}{100.101}+...+\dfrac{1}{198.199}\)
\(S< \dfrac{1}{99}-\dfrac{1}{100}+\dfrac{1}{100}-\dfrac{1}{101}+...+\dfrac{1}{198}-\dfrac{1}{199}\)
\(S< \dfrac{1}{99}-\dfrac{1}{199}< \dfrac{1}{99}\) (đpcm)