Các câu hỏi tương tự
\(\frac{2017a^2+ab}{2018a^2-8b^2}=\frac{2017c^2+cd}{2018c^2+8d}\)
Cho \(\frac{a}{b}=\frac{c}{d}\), chứng minh rằng
a) \(\frac{ab}{cd}=\frac{a^2+b^2}{c^2+d^2}\)
b) \(\frac{7a^2+3ab}{11a^2-8b^2}=\frac{7c^2+3cd}{11c^2-8d^2}\)
Cho \(\frac{a}{b}=\frac{c}{d}\)
Chứng minh rằng
\(1.\frac{ab}{cd}=\frac{a^2-b^2}{c^2-d^2}\) \(2.\frac{2a+b}{2a-b}=\frac{2c+d}{2c-d}\) \(3.\left(\frac{a+b}{c+d}\right)^3=\frac{a^3-b^3}{c^3-d^3}\) \(4.\frac{7a^2+3ab}{11a^2-8b^2}=\frac{7c^2+3cd}{11c^2-8d^2}\)
Cho tỉ lệ thức \(\frac{a}{b}=\frac{c}{d}\) . Chứng minh rằng ta có tỉ lệ thức sau :
\(\frac{2018a^2+2019b^2}{2018a^2-2019b^2}=\frac{2018c^2+2019d^2}{2018c^2-2019d^2}\)
1) Cho \(\frac{a}{b}=\frac{c}{d}\). Chứng minh: \(\frac{a}{3a+b}=\frac{c}{3c+d}\)
2) Cho\(\frac{a}{b}=\frac{c}{d}\). Chứng minh:
a) \(\frac{a^2-d^2}{c^2-d2}=\frac{ab}{cd}\)
b) \(\frac{\left(a-b\right)^2}{\left(c-d\right)^2}=\frac{ab}{cd}\)
Cho tỉ lệ thức a/b=c/d CMR :
a) \(\frac{7a+8b}{7a-8b}=\frac{7c+8d}{7c-8d}\)
b) \(\frac{11a-5b}{3a+4b}=\frac{11c-5d}{3c+4d}\)
c) \(\frac{a.b}{c.d}=\frac{a^2-b^2}{c^2-d^2}\)
d) \(\frac{\left(a+b\right)^2}{\left(c+d\right)^2}=\frac{a^2+b^2}{c^2+d^2}\)
e) \(\frac{ab}{cd}=\frac{\left(a-b\right)^2}{\left(c-d\right)^2}\)
help me 3 l-i-k-e
Cho \(\frac{a}{b}=\frac{c}{d}\)
Chứng minh rằng:
a) \(\frac{ab}{cd}=\frac{a^2-b^2}{c^2-d^2}\)
b) \(\frac{\left(a+b\right)^2}{\left(c+d\right)^2}=\frac{ab}{cd}\)
Cho \(\frac{a}{b}=\frac{c}{d}.\) Chứng minh:
\(a.\) \(\frac{a^2-b^2}{c^2-d^2}=\frac{ab}{cd}\)
\(b.\) \(\frac{\left(a-b\right)^2}{\left(c-d\right)^2}=\frac{ab}{cd}\)
Cho \(\frac{a}{b}=\frac{c}{d}\) . Chứng minh:
a, \(\frac{a^2-b^2}{c^2-d^2}=\frac{ab}{cd}\)
b,\(\frac{\left(a-b\right)^2}{\left(c-d\right)^2}=\frac{ab}{cd}\)