=1/1 -1/2 +1/3-1/4+1/4-1/5+...+1/99-1/100
=1/2-1/100=49/100
=1/1 -1/2 +1/3-1/4+1/4-1/5+...+1/99-1/100
=1/2-1/100=49/100
cho\(A=\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{4.5}+.....+\frac{1}{99.100}\)
CMR:\(\frac{7}{12}< A< \frac{5}{6}\)
cho\(A=\frac{1}{1.2}+\frac{1}{3.4}+.........+\frac{1}{99.100}CMR\frac{7}{12}< A< \frac{5}{6}\)
Cho A=\(\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+....+\frac{1}{99.100}\)
CMR:\(\frac{7}{12}< A< \frac{5}{6}\)
CHO : \(M=\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+.......+\frac{1}{97.98}+\frac{1}{99.100}\)
Chứng Minh: \(\frac{7}{12}< M< \frac{5}{6}\)
cho A = \(\frac{1}{1.2}+\frac{1}{3.4}+......+\frac{1}{99.100}\)
CMR : \(\frac{7}{12}< A< \frac{5}{6}\)
\(choA=\frac{1}{1.2}+\frac{1}{3.4}+...+\frac{1}{99.100}\)
\(CMR:\frac{7}{12}< A< \frac{5}{6}\)
1, CMR: \(\frac{7}{12}<\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{97.98}+\frac{1}{99.100}<\frac{5}{6}\)
2, CMR: \(\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{47.48}+\frac{1}{49.50}=\frac{1}{26}+\frac{1}{27}+\frac{1}{28}+...+\frac{1}{49}+\frac{1}{50}\)
Haizzzzzzzz............. Vừa mới ik thi tháng về (=_=) . Có bài này khó
Các anh , các chị giúp em với ạ !
Cho \(A=\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{99.100}\text{. Chứng minh rằng : }\frac{7}{12}< A< \frac{5}{6}\)
1, CMR: \(\frac{7}{12}<\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{97.98}+\frac{1}{99.100}<\frac{5}{6}\)
2, CMR: \(\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{47.48}+\frac{1}{49.50}=\frac{1}{26}+\frac{1}{27}+\frac{1}{28}+...+\frac{1}{49}+\frac{1}{50}\)