Theo định luật nút ta có :
\(I_1=I_2+I_{V_2}=>\dfrac{U_{R_1}}{R}=\dfrac{U_{R_2}}{R}+\dfrac{U_{V_1}}{R_V}\)
( Với : \(U_{R_1}=U_{V_1}-U_{V_2}=6-2=4V\))
\(=>\dfrac{4}{R}=\dfrac{2}{R}+\dfrac{2}{R_V}=>R=R_V\)
\(I=I_{V_1}+I_{R_1}=\dfrac{U_{V_1}}{R_V}+\dfrac{U_{V_2}}{\dfrac{R.R_V}{R+R_v}}=\dfrac{6}{R}+\dfrac{4}{R}=\dfrac{10}{R}\)
\(=>U_{AD}=U_R+U_{V_1}=I.R+6=\dfrac{10}{R}.R+6=16V\)