Các câu hỏi tương tự
cho \(\frac{a}{b}\)=\(\frac{c}{d}\)
chứng minh \(\frac{3a^2+c^2}{3b^2+d^2}\)=\(\frac{\left(a+c\right)^2}{\left(b+d\right)^2}\)
1/ cho \(\frac{a}{b}=\frac{c}{d}\)chứng minh rằng:
a) \(\frac{a.b}{c.d}=\frac{\left(a+b\right)^2}{\left(c+d\right)^2}\)
b)\(\frac{a,d}{c.b}=\frac{\left(a+b\right).\left(a-b\right)}{\left(c+d\right).\left(c-d\right)}\)
2/ cho \(a.b=c^2\)chứng minh : \(\frac{a}{b}=\frac{\left(2a+3c\right)^2}{\left(2c+3b\right)^2}\)
Cho a/b = c/d. Chứng minh:
a) \(\frac{\left(a+c\right)^2}{\left(b+d\right)^2}=\frac{ac}{bd}\)
b) \(\frac{a^2}{b^2}=\frac{3a^2-2ac}{3b^2-2bd}\)
Cho dãy tỉ số bằng nhau \(\frac{3a+b+c+d}{a}=\frac{a+3b+c+d}{b}=\frac{a+b+3c+d}{c}=\frac{a+b+c+3d}{d}\)
Tính Q=\(\left(\frac{a+b}{c+d}\right)^2+\left(\frac{b+c}{a+d}\right)^2+\left(\frac{c+d}{a+b}\right)^2+\left(\frac{a+d}{b+c}\right)^2\)
CHO \(\frac{a}{b}=\frac{c}{d}\)và \(b+d\ne0\).CHỨNG TỎ : \(\frac{3a^2+c^2}{3b^2+d^2}=\frac{\left(a+c\right)^2}{\left(b+d\right)^2}\)
1) Cho \(\frac{a}{b}=\frac{c}{d}\). Chứng minh: \(\frac{a}{3a+b}=\frac{c}{3c+d}\)
2) Cho\(\frac{a}{b}=\frac{c}{d}\). Chứng minh:
a) \(\frac{a^2-d^2}{c^2-d2}=\frac{ab}{cd}\)
b) \(\frac{\left(a-b\right)^2}{\left(c-d\right)^2}=\frac{ab}{cd}\)
Cho \(\frac{a}{b}=\frac{c}{d}\), chứng minh rằng:
\(\frac{\left(a-b\right)^3}{\left(c-d\right)^3}=\frac{3a^2+2b^2}{3c^2+2d^2}\)
Cho \(\frac{a}{b}=\frac{c}{d}.\)Chứng minh.
a)\(\frac{3a+5b}{3a-5b}=\frac{3c+5d}{3c-5d}\)
b)\(\left(\frac{a+b}{c+d}\right)^2=\frac{a^2+b^2}{c^2+d^2}\)
\(\frac{a.b}{c.d}=\frac{\left(a-b\right)^2}{\left(c-d\right)^2}\)
cho \(\frac{a}{b}=\frac{c}{d}\)
Chứng minh:a) \(\frac{a}{b}=\frac{11a+9c}{11b+9d}\)
b) \(\frac{3a^2+5c^2}{3b^2+5d^2}=\frac{\left(a+c\right)^2}{\left(b+d\right)^2}\)