Các câu hỏi tương tự
Chứng minh:
A = \(\frac{1}{101}+\frac{1}{102}+\frac{1}{103}+.....+\frac{1}{199}+\frac{1}{200}>\frac{7}{12}\)
Chứng minh rằng: \(C=\frac{1}{101}+\frac{1}{102}+\frac{1}{103}+...+\frac{1}{200}>\frac{7}{12}\)
Cho \(A=\frac{1}{101}+\frac{1}{102}+\frac{1}{103}+...+\frac{1}{200}\)
CMR A>\(\frac{7}{12}\)
A>\(\frac{5}{8}\)
Cho \(A=\frac{1}{101}+\frac{1}{102}+\frac{1}{103}+...+\frac{1}{200}\)
CMR \(A>\frac{7}{12}\)
\(A>\frac{5}{8}\)
1)
\(Cho:\frac{1}{20}+\frac{1}{21}+\frac{1}{22}+...+\frac{1}{200}\)
Chứng minh: \(A>\frac{9}{10}\)
2)
Cho \(B=\frac{1}{101}+\frac{1}{102}+\frac{1}{103}+...+\frac{1}{200}\)
Chứng minh \(B>\frac{7}{12}\)
1)
Cho \(\frac{1}{20}+\frac{1}{21}+\frac{1}{22}+...+\frac{1}{200}\)
Chứng minh: \(A>\frac{9}{10}\)
2)
Cho \(B=\frac{1}{101}+\frac{1}{102}+\frac{1}{103}+...+\frac{1}{200}\)
Chứng minh: \(B>\frac{7}{12}\)
\(Cho A=\frac{1}{101}+\frac{1}{102}+\frac{1}{103}+\frac{1}{104}+.....+\frac{1}{200}\). Chứng tỏ: \(A>\frac{7}{12}\)
Cho \(A=\frac{1}{101}+\frac{1}{102}+\frac{1}{103}+...+\frac{1}{200}\)
cmr \(A< \frac{7}{12}\)
cho A=\(\frac{1}{101}+\frac{1}{102}+\frac{1}{103}+...+\frac{1}{200}\)
CMR: a) A > \(\frac{7}{12}\)
b) A > \(\frac{5}{8}\)