PTHH: K2O + H2 -to-> 2K + H2O (1)
PbO + H2 -to-> Pb + H2O (2)
Al2O3 + 3H2 -to-> 2Al + 3H2O (3)
Fe3O4 +4H2 -to-> 3Fe + 4H2O (4)
BaO + H2 -to-> Ba + H2O (5)
Theo các PTHH và đề bài, ta có:
\(n_{K\left(1\right)}=2.n_{K_2O\left(1\right)}=2.0,1=0,2\left(mol\right)\\ =>m_{K\left(1\right)}=0,2.39=7,8\left(g\right)\)
\(n_{Pb\left(2\right)}=n_{PbO\left(2\right)}=0,2\left(mol\right)\\ =>m_{Pb\left(2\right)}=0,2.207=41,4\left(g\right)\)
\(n_{Al\left(3\right)}=2.n_{Al_2O_3\left(3\right)}=2.0,2=0,4\left(mol\right)\\ =>m_{Al\left(3\right)}=0,4.27=10,8\left(g\right)\)
\(n_{Fe\left(4\right)}=3.n_{Fe_3O_4\left(4\right)}=3.0,1=0,3\left(mol\right)\\ =>m_{Fe\left(4\right)}=0,3.56=16,8\left(g\right)\)
\(n_{Ba\left(5\right)}=n_{BaO\left(5\right)}=0,05\left(mol\right)\\ =>m_{BaO\left(5\right)}=0,05.153=7,65\left(g\right)\)
