Question

Câu 1:

\(|x-\frac{2}{5}|+\frac{1}{2}=\frac{3}{4}\)

\(\left|5-3x\right|+\frac{2}{3}=\frac{11}{6}\)

\(\frac{1}{5}-\left|\frac{1}{5}-x\right|=\frac{1}{5}\)

\(\left|x+\frac{3}{4}\right|-\frac{1}{2}=6^2\)

Cần gấp vào một tiếng sau ai onl trả lời gấp xin cám ơn :33

Answer 1

\(\left|x-\frac{2}{5}\right|+\frac{1}{2}=\frac{3}{4}\)

=> \(\left|x-\frac{2}{5}\right|=\frac{1}{4}\)

=> \(\orbr{\begin{cases}x-\frac{2}{5}=\frac{1}{4}\\x-\frac{2}{5}=-\frac{1}{4}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{13}{20}\\x=\frac{3}{20}\end{cases}}\)

b) \(\left|5-3x\right|+\frac{2}{3}=\frac{11}{6}\)

=> \(\left|5-3x\right|=\frac{7}{6}\)

=> \(\orbr{\begin{cases}5-3x=\frac{7}{6}\\5-3x=-\frac{7}{6}\end{cases}}\Rightarrow\orbr{\begin{cases}3x=\frac{23}{6}\\3x=\frac{37}{6}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{23}{18}\\x=\frac{37}{18}\end{cases}}\)

c) \(\left|x+\frac{3}{4}\right|-\frac{1}{2}=6^2\)

=> \(\left|x+\frac{3}{4}\right|=36,5\)

=> \(\orbr{\begin{cases}x+\frac{3}{4}=36,5\\x+\frac{3}{4}=-36,5\end{cases}}\Rightarrow\orbr{\begin{cases}x=35,75\\x=-37,25\end{cases}}\)

Answer 2

a) \(\left|x-\frac{2}{5}\right|+\frac{1}{2}=\frac{3}{4}\Leftrightarrow\left|x-\frac{2}{5}\right|=\frac{1}{4}\)\(\Leftrightarrow\orbr{\begin{cases}x-\frac{2}{5}=\frac{1}{4}\\x-\frac{2}{5}=\frac{-1}{4}\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\frac{13}{20}\\x=\frac{3}{20}\end{cases}}}\)

b) \(\left|5-3x\right|+\frac{2}{3}=\frac{11}{6}\Leftrightarrow\left|5-3x\right|=\frac{7}{6}\)\(\Leftrightarrow\orbr{\begin{cases}5-3x=\frac{7}{6}\\5-3x=\frac{-7}{6}\end{cases}\Leftrightarrow\orbr{\begin{cases}3x=\frac{23}{6}\\3x=\frac{37}{6}\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=\frac{23}{18}\\x=\frac{37}{18}\end{cases}}}\)

c) \(\frac{1}{5}-\left|\frac{1}{5}-x\right|=\frac{1}{5}\Leftrightarrow\left|\frac{1}{5}-x\right|=0\Leftrightarrow x=\frac{1}{5}\)

Answer 3

d) \(\left|x+\frac{3}{4}\right|-\frac{1}{2}=6^2\Leftrightarrow\left|x+\frac{3}{4}\right|=\frac{73}{2}\Leftrightarrow\orbr{\begin{cases}x+\frac{3}{4}=\frac{73}{2}\\x+\frac{3}{4}=\frac{-73}{2}\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\frac{143}{4}\\x=\frac{-149}{4}\end{cases}}}\)

Answer 4

a) \(\left|x-\frac{2}{5}\right|+\frac{1}{2}=\frac{3}{4}\)

\(\Leftrightarrow\left|x-\frac{2}{5}\right|=\frac{1}{4}\)

\(\Leftrightarrow\orbr{\begin{cases}x-\frac{2}{5}=\frac{-1}{4}\\x-\frac{2}{5}=\frac{1}{4}\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{3}{20}\\x=\frac{13}{20}\end{cases}}\)

Vậy \(x=\frac{3}{20}\)hoặc \(x=\frac{13}{20}\)

b) \(\left|5-3x\right|+\frac{2}{3}=\frac{11}{6}\)\(\Leftrightarrow\left|5-3x\right|=\frac{7}{6}\)

\(\Leftrightarrow\orbr{\begin{cases}5-3x=\frac{-7}{6}\\5-3x=\frac{7}{6}\end{cases}}\Leftrightarrow\orbr{\begin{cases}3x=\frac{37}{6}\\3x=\frac{23}{6}\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{37}{18}\\x=\frac{23}{18}\end{cases}}\)

Vậy \(x=\frac{37}{18}\)hoặc \(x=\frac{23}{18}\)

c) \(\frac{1}{5}-\left|\frac{1}{5}-x\right|=\frac{1}{5}\)\(\Leftrightarrow\left|\frac{1}{5}-x\right|=0\)

\(\Leftrightarrow\frac{1}{5}-x=0\)\(\Leftrightarrow x=\frac{1}{5}\)

Vậy \(x=\frac{1}{5}\)

d) \(\left|x+\frac{3}{4}\right|-\frac{1}{2}=6^2\)\(\Leftrightarrow\left|x+\frac{3}{4}\right|-\frac{1}{2}=36\)

\(\Leftrightarrow\left|x+\frac{3}{4}\right|=\frac{73}{2}\)\(\Leftrightarrow\orbr{\begin{cases}x+\frac{3}{4}=\frac{-73}{2}\\x+\frac{3}{4}=\frac{73}{2}\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{-149}{4}\\x=\frac{143}{4}\end{cases}}\)

Vậy \(x=\frac{-149}{4}\)hoặc \(x=\frac{143}{4}\)

Answer 5

Thêm bài nữa nhé mn :33

\(x:\left(\frac{-4}{21}\right)=2\frac{4}{5}\)