Question

Bài 1 Tìm các số nguyên x , y,z

c \(\frac{-4}{8}\)=\(\frac{x}{-10}\)=\(\frac{-7}{y}\)=\(\frac{z}{-24}\)

d \(\frac{x}{2}\)=\(\frac{8}{x}\)

làm hộ các bạn ơi

Answer 1

\(\frac{-4}{8}=\frac{x}{-10}=\frac{-7}{y}=\frac{z}{-24}\)

\(\Rightarrow\frac{-4}{8}=\frac{x}{-10}\Leftrightarrow x=\frac{-10.\left(-4\right)}{8}=5\)

\(\Rightarrow\frac{-4}{8}=\frac{-7}{y}\Leftrightarrow y=\frac{-7.8}{-4}=14\)

\(\Rightarrow\frac{-4}{8}=\frac{z}{-24}\Leftrightarrow z=\frac{-24.\left(-4\right)}{8}=12\)

Vậy 

\(\frac{x}{2}=\frac{8}{x}\)

\(\Rightarrow x.x=2.8\)

\(x^2=16\)

\(x^2=\left(\pm4\right)^2\)

\(\Rightarrow x=\pm4\)

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