\(a-\left(-b-c\right)=a+b+c=a+\left(b+c\right)\)
\(-\left(a-b\right)+\left(c-d\right)=b-a+c-d=\left(b+c\right)-\left(a+d\right)\)
B1:
Ta có: a-(-b-c)=a-(-b)-(-c)=a+b+c=a+(b+c)
=>a-(-b-c)=a+(b+c)
=>ĐPCM
B2:
Ta có: -(a-b)+(c-d)=-a-(-b)+c+(-d)=-a+b+c-d=b+c-a-d=b+c-a-(+d)=(b+c)-(a+d)
=>-(a-b)+(c+d)=(b+c)-(a+d)
=>ĐPCM