Đặt \(C=3+3^3+3^5+..+3^{203}\)
\(\Rightarrow B=1+C\Rightarrow8B=8+8C\)
\(3^2.C=9.C=3^3+3^5+3^7+...+3^{205}\)
\(8.C=9.C-C=3^{205}-3\)
\(\Rightarrow8B=8+3^{205}-3=3^{205}+5\)
\(\Rightarrow8B-5=3^{5x}\Leftrightarrow3^{205}+5-5=3^{5x}\Leftrightarrow3^{205}=3^{5x}\Rightarrow205=5x\Rightarrow x=205:5=41\)