A và B dễ
Bài 2:
sai đề bài vì ngay từ cái phép tính đầu đã ko theo quy luật rồi
\(A=\frac{-3}{5}-\frac{2}{5}+2\)
\(A=-1+2=1\)
\(B=\left(6-\frac{14}{5}\right).\frac{25}{8}-\frac{8}{5}=\frac{1}{4}\)
nÀ NÍ sao lại = đây là dấu trừ hay cộng 1/4
\(B=\left(6-\frac{14}{5}\right).\frac{25}{8}-\frac{8}{5}:\frac{1}{4}\)
\(B=\frac{16}{5}.\frac{25}{8}-\frac{32}{5}\)
\(B=10-\frac{32}{5}=\frac{18}{5}\)
\(B=\left(6-2\frac{4}{5}\right)\times3\frac{1}{8}-1\frac{3}{5}\div\frac{1}{4}\)
\(A=-\frac{3}{5}+\left(-\frac{2}{5}+2\right).\)
\(A=-\frac{3}{5}+-\frac{2}{5}+2\)
\(A=\left(-1\right)+2=1\)
\(B=\left(6-2\frac{4}{5}\right).3\frac{1}{8}-1\frac{3}{5}:\frac{1}{4}\)
\(B=\left(6-\frac{14}{5}\right).\frac{25}{8}-\frac{8}{5}:\frac{1}{4}\)
\(B=\left(\frac{30}{5}-\frac{14}{5}\right).\frac{25}{8}-\frac{8}{5}:\frac{1}{4}\)
\(B=\frac{16}{5}.\frac{25}{8}-\frac{8}{5}:\frac{1}{4}\)
\(B=\frac{400}{40}-\frac{32}{5}\)
\(B=10-\frac{32}{5}=\frac{18}{5}\)
\(A=\frac{5}{1\cdot7}+\frac{5}{4\cdot7}+\frac{5}{7\cdot10}+...+\frac{5}{101\cdot104}\)
\(A=5\left(\frac{1}{1\cdot7}+\frac{1}{4\cdot7}+\frac{1}{7\cdot10}+...+\frac{1}{101\cdot104}\right)\)
\(A=5\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-...-\frac{1}{101}+\frac{1}{101}-\frac{1}{104}\right)\)
\(A=5\left(1-\frac{1}{104}\right)\)
\(A=5.\frac{103}{104}=\frac{515}{104}\)