\(a,4\frac{1}{3}\left[\frac{1}{2}-\frac{1}{6}\right]\le x\le-\frac{2}{3}\left[\frac{1}{3}\cdot\frac{1}{2}-\frac{3}{4}\right]\)
=> \(\frac{13}{3}\left[\frac{3}{6}-\frac{1}{6}\right]\le x\le-\frac{2}{3}\left[\frac{1}{6}-\frac{3}{4}\right]\)
=> \(\frac{13}{3}\cdot\frac{1}{3}\le x\le-\frac{2}{3}\cdot\left[\frac{2}{12}-\frac{9}{12}\right]\)
=> \(\frac{13}{9}\le x\le-\frac{2}{3}\cdot\left[-\frac{7}{12}\right]\)
=> \(\frac{13}{9}\le x\le-\frac{1}{3}\cdot\left[-\frac{7}{6}\right]\)
=> \(\frac{13}{9}\le x\le\frac{7}{18}\)
Đến đây tự tìm x