\(x+\frac{2}{3}=\frac{1}{6}\)
\(x=\frac{1}{6}-\frac{4}{6}\)
\(x=-\frac{3}{6}=-\frac{1}{2}\)
a) (x+2/3)=1/6
=>x=1/6-2/3
=>x=-1/2
b) (x-3/4)+1= 1 và 2/3
=> (x-3/4)+1=5/3
=> x-3/4 =2/3
=> x=17/12
c, (x)-1=(-1/4)
=>x=-1/4+1
=>x=3/4
a) \(X+\frac{2}{3}=\frac{1}{6}\)
=>\(X=\frac{1}{6}-\frac{2}{3}=\frac{1}{6}-\frac{4}{6}=\frac{-3}{6}=\frac{-1}{2}=-0.5\)
b) \(\left(X-\frac{3}{4}\right)+1=1\)
=>\(X-\frac{3}{4}=0\)
=>\(X=\frac{3}{4}\)
\(\left(X-\frac{3}{4}\right)+1=\frac{2}{3}\)
=>\(X-\frac{3}{4}=-\frac{1}{3}\)
=>\(X=\frac{5}{12}\)
c) \(X-1=-\frac{1}{4}\)
\(X=-\frac{1}{4}+1=\frac{3}{4}\)