hông biết mới học lớp 6 làm seo biết đc toán lớp 8 tự nghĩ đi nha
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a, P = x2- 2x + 3
P= ( x2 -2x +1) +2
= ( x-1)2 +2
ta có : ( x -1)2 \(\ge0\forall x\)=> (x-1)2 +2 \(\ge0+2\)=> P\(\ge\)2
dấu = xảy ra <=> ( x-1)2=0
=> x-1=0 => x=1
vậy GTNN của P=2 tại x=1
b, M= -( x2-2x+5)
M= - [( x2 -2x +1) +4]
= -( x-1)2-4
ta có: -( x-1)2 \(\le0\forall x\) => -( x-1)2 -4 \(\le0-4\) => M \(\le-4\)
dấu = xảy ra <=> -( x-1)2 =0
=> ( x-1 )20 => x-1 =0
=> x=1
vậy GTLN của M = -4 tại x =1
