\(9x^2-1=\left(3x-1\right)\left(2x-3\right)\)
\(\Leftrightarrow\left(3x+1\right)\left(3x-1\right)=\left(3x-1\right)\left(2x-3\right)\)
\(\Leftrightarrow\left(3x-1\right)\left(3x+1-2x+3\right)=0\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=\frac{1}{3}\\x=-4\end{matrix}\right.\)
1) 9x2 - 1 = 6x2 -9x - 2x + 3
=> 9x2 - 6x2 + 2x + 9x = 3 + 1
=> 3x2 + 11x - 4 = 0
=> 3x2 + 12x - x - 4 =0
=> (x-4)(3x - 1) = 0
=> x = 4 hoặc x = 1/3
2) 18x2 + 12x + 2 = 3x2 - 6x + x - 2
=> 15x2 - 17x + 4 = 0
=> 15x2 - 5x -12x + 4 =0
=> (3x - 1)(5x - 4) = 0
=> x = 1/3 hoặc x = 4/5
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\(2\left(9x^2+6x+1\right)=\left(3x+1\right)\left(x-2\right)\)
\(\Leftrightarrow\left(3x+1\right)\left(6x+2-x+2\right)=0\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=-\frac{1}{3}\\x=-\frac{4}{5}\end{matrix}\right.\)
