Question

7 chia hết cho n +1 

Answer 1

7 chia hết cho 6+1

Answer 2

\(\Leftrightarrow n+1\in\left\{1;-1;7;-7\right\}\)

hay \(n\in\left\{0;-2;6;-8\right\}\)

Answer 3

\(\Rightarrow n+1\inƯ\left(7\right)=\left\{1;-1;7;-7\right\}\)

\(\Rightarrow x\in\left\{0;-2;6;-8\right\}\)

Answer 4

để :\(7⋮n+1\) thì

\(n+1\in U\left(7\right)=\left\{\pm1;\pm7\right\}\)

do đó:\(n+1=-1\Rightarrow n=-2\)

\(n+1=1\Rightarrow n=0\)

\(n+1=-7\Rightarrow n=-8\)

\(n+1=7\Rightarrow n=6\)

Answer 5

0;-2;6;-8

Answer 6

⇒n+1∈Ư(7)={1;−1;7;−7}