`@` `\text {Ans}`
`\downarrow`
`5^6 \div 5^3 + 2^2*2^3`
`= 5^3 + 2^5`
`= 125+32`
`=``157`
`19^7 \div 19^5 + 4*4^2`
`= 19^(7-5) + 4^(1+2)`
`= 19^2 + 4^3`
`= 361 + 64`
`=``425`
\(2^5\cdot7+3^{2019}\div3^{2018}?\)
`= 224 + 3`
`= 227`
`17*3^2 - 5^15 \div 5^13 + 39^0`
`= 153 - 5^2 + 1`
`= 153 - 125 + 1`
`= 153 - 124`
`=29`
A=(5+5mu2)+(5mu3+5mu4)+(5mu5+5mu6)+(5mu7+5mu8)
5mu13 : 5mu10 - 25*2mu2
bai1
5mu3+3mu5
bai2
(x-1)mu3=125
720/(41-(2*x-5))=2mu 3*5
bai3
1 phan 9 * 3 mu 4 * 3 mu n =3 mu 7
(2 mu 2 chia 4)* 2 mu n = 4
bai4
2 * 2mu2 * 2mu3 * 2mu4 *.......*2 mu100
2mu17+15mu4).(3mu19-2mu17).(2mu4-4mu2)
4mu2:4.3mu3-2mu2+7
\(S=\dfrac{2mu2}{1.2}+\dfrac{2mu2}{2.3}+\dfrac{2mu2}{3.4}+...+\dfrac{2mu2}{2022.2023}\)
(mu = mũ)
hãy viết thành một bình phương
1mu3+2mu3+3mu3+4mu3+5mu3
1mu3+2mu3+3mu3+4mu3+5mu3+6mu3
20+2.(x+3)=5mu2.4
(2x-6)=2.5mu4:5mu3
A=3mu2+3mu2+2mu2+2mu2+.........=1mu2+1mu2
