\(4^x+10.4^x=1280\)
<=>\(11.4^x=1280\)
<=>\(4^x=\frac{1280}{11}=>saiđề\)
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\(4^x+10.4^x=1280\)
<=>\(11.4^x=1280\)
<=>\(4^x=\frac{1280}{11}=>saiđề\)
4^x+2.5.4^x = 1280
4x+2.5.4x=1280
4x+2.5.4x=1280
33.x+29=488
215-2.(36+x)=45
1280:[18+(x-9)]=24.4
43:x=8
4x+2*5*4x=1280
(32-x)*22*3-5=43
2x+3+2x+1=1280
Ai giup minh tra loi voi:
2x + 2x+1=96
4x+2 × 5 × 4x = 1280
1280:[109-(3x-7):]=40. Tìm x
tìm x :
a) (x+3)+(x+5)+.......+(x+53)=754
b)9+11+13+...+(2x+1)=1280
f)(3x-9).(x-7)=0