\(4x-12-2005-1-3x=0\\ x-2018=0\\ x=2018\)
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Bài 2: Phương trình bậc nhất một ẩn và cách giải
Các câu hỏi tương tự
giải phương trình 1)dfrac{1-6x}{x-2}+dfrac{9x+4}{x+2}dfrac{xleft(3x-2right)+1}{x^2-4}2) dfrac{3x+2}{3x-2}-dfrac{6}{2+3x}dfrac{9x^2}{9x^2-4}3) dfrac{x+5}{3x-6}-dfrac{1}{2}dfrac{2x-3}{2x-4}4) dfrac{x-1}{x}+dfrac{1}{x+1}dfrac{2x-1}{2x^2+2}5) dfrac{2}{x+1}+dfrac{3x+1}{x+1}dfrac{1}{left(x+1right)left(x-2right)}
Đọc tiếp
giải phương trình 1)\(\dfrac{1-6x}{x-2}+\dfrac{9x+4}{x+2}=\dfrac{x\left(3x-2\right)+1}{x^2-4}\)2) \(\dfrac{3x+2}{3x-2}-\dfrac{6}{2+3x}=\dfrac{9x^2}{9x^2-4}\)3) \(\dfrac{x+5}{3x-6}-\dfrac{1}{2}=\dfrac{2x-3}{2x-4}\)4) \(\dfrac{x-1}{x}+\dfrac{1}{x+1}=\dfrac{2x-1}{2x^2+2}\)5) \(\dfrac{2}{x+1}+\dfrac{3x+1}{x+1}=\dfrac{1}{\left(x+1\right)\left(x-2\right)}\)
Giải phương trình 1, dfrac{1-6x}{x-2}+dfrac{9x+4}{x+2}dfrac{xleft(3x-2right)+1}{x^2-4}2, dfrac{3x+2}{3x-2}-dfrac{6}{2-3x}dfrac{9x^2}{9x^2-4}3, dfrac{x-1}{x}+dfrac{1}{x+1}dfrac{2x-1}{2x^2+2}4, dfrac{2}{x+1}+dfrac{3x+1}{x+1}dfrac{1}{left(x+1right)left(x-2right)}5, dfrac{x+5}{3x-6}-dfrac{1}{2}dfrac{2x-3}{2x-4}
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Giải phương trình
1, \(\dfrac{1-6x}{x-2}+\dfrac{9x+4}{x+2}=\dfrac{x\left(3x-2\right)+1}{x^2-4}\)
2, \(\dfrac{3x+2}{3x-2}-\dfrac{6}{2-3x}=\dfrac{9x^2}{9x^2-4}\)3, \(\dfrac{x-1}{x}+\dfrac{1}{x+1}=\dfrac{2x-1}{2x^2+2}\)4, \(\dfrac{2}{x+1}+\dfrac{3x+1}{x+1}=\dfrac{1}{\left(x+1\right)\left(x-2\right)}\)5, \(\dfrac{x+5}{3x-6}-\dfrac{1}{2}=\dfrac{2x-3}{2x-4}\)
Giải các phương trình
1,\(3x-1=0\\\) 4, \(\dfrac{x}{3}-\dfrac{x}{5}=4\)
2, \(2-x=3x+1\) 5, \(\dfrac{x-1}{4}+\dfrac{2x+1}{6}=\dfrac{3}{2}\)
3, \(2\left(x-2\right)-1=5x\)
1) (3x-2)/3-2=(4x+1)/4
2) (x-3)/4+(2x-1)/3=(2-x)/6
3) 1/2 (x+1)+1/4 (x+3)=3-1/3 (x+2)
4) (x+4)/5-x+4=x/3-(x-2)/2
5) (4-5x)/6=2(-x+1)/2
6) (-(x-3))/2-2=5(x+2)/4
7)2(2x+1)/5-(6+x)/3=(5-4x)/15
8) (7-3x)/2-(5+x)/5=1
9)(x-1)/2+3(x+1)/8=(11-5x)/3
10)(3+5x)/5-3=(9x-3)/4
bài 2
a 0,75x (x +5 )= x+5 (3- 1,25x)
b\(\frac{4}{5}x-3=\frac{1}{5}x\left(4x-15\right)\)
c(x-3) -\(\frac{\left(x-3\right)\left(2x-5\right)}{6}=\frac{\left(x-3\right)\left(3-x\right)}{4}\)
d \(\frac{\left(3x+1\right)\left(3x-2\right)}{3}+5\left(3x+1\right)=\frac{2\left(2x+1\right)\left(3x+1\right)}{3}+2x\left(3x+1\right)\)
7+2x=22-3x
x-12+4x=25+2x-1
7-(2x+4)=-(x+4)
8x-3=5x+12
x+2x+3x-19=3x+5
(x-1)-(2x-1)=9-x
a) (4x+1) (3x+7/3-5x. +1) = (x-4) (3x+7/5x-3. -1)
b) (x^2+3x+1) (4x-3/3x+1. +2)=(4x-7) (4x-3/3x+1. +2)
(+1; -1; +2 không phải mẫu nhé. Nó là 1 số riêng)
A) 1/4(x+3)=3-1/2(x+1)-1/3(x+2)
B) 3x-11/11-x/3=3x-5/7-5x-3/9
C) x-3/17(2x-1)=7/34(1-2x)+10x-3
1) (x+5)(x+2)-3(4x-3)=(5-x)2
2) (x+2)3-(x-2)3=12x(x-1)-8
3) 3x(12x-4)-9x(4x-3)=30
4) (12x-5)(4x-1)+(3x-7)(1-16x)=81