\(4\cdot\left(x-12\right)=2x+164\)
\(\Leftrightarrow4x-48=2x+164\)
\(\Leftrightarrow4x-2x=164+48\)
\(\Leftrightarrow2x=212\Rightarrow x=106\)
Sửa đề : \(\frac{1}{1.5}+\frac{1}{5.9}+...+\frac{1}{401.405}+x=2\frac{1}{405}\)
\(\Leftrightarrow\frac{1}{4}\cdot\left(1-\frac{1}{5}+\frac{1}{5}-\frac{1}{9}+...+\frac{1}{401}-\frac{1}{405}\right)+x=\frac{811}{405}\)
\(\Leftrightarrow\frac{1}{4}\cdot\left(1-\frac{1}{405}\right)+x=\frac{811}{405}\)
\(\Leftrightarrow\frac{1}{4}\cdot\frac{404}{405}+x=\frac{811}{405}\)
\(\Leftrightarrow\frac{101}{405}+x=\frac{811}{405}\Rightarrow x=\frac{142}{81}\)
4x(X-12)=2xX+164
2x2x(X-12)=2xX+2x82
2x(2X-24)=2x(X+82)
2X-24=X+82
2X=X+82+24
2X=X+106
X=106
sửa bạn nhé 1\(\frac{1}{4}\)x X - \(\frac{3}{5}\)= \(\frac{4}{5}\)x X + 75%
\(1\frac{1}{4}\)xX-\(\frac{3}{5}=\frac{4}{5}\)xX+35%
\(\frac{5}{4}\)xX-\(\frac{3}{5}=\frac{4}{5}\)xX+\(\frac{7}{20}\)
\(\frac{5}{4}\)xX\(=\frac{4}{5}\)xX+\(\frac{7}{20}+\frac{3}{5}\)
\(\frac{5}{4}\)xX\(=\frac{4}{5}\)xX+\(\frac{19}{20}\)
\(\frac{19}{20}\)\(=\frac{5}{4}\)xX-\(\frac{4}{5}\)xX
\(\frac{19}{20}=\left(\frac{5}{4}-\frac{4}{5}\right)\)xX
\(\frac{19}{20}=\frac{9}{20}\)xX
X\(=\frac{19}{20}:\frac{9}{20}\)
X\(=\frac{19}{9}\)