Question

1/(a-b)(a-c) + 1/(b-c)(b-a) + 1/(c-a)(c-b)

rút gọn biểu thức trên

 

Answer 1

\(\frac{1}{\left(a-b\right)\left(a-c\right)}+\frac{1}{\left(b-c\right)\left(b-a\right)}+\frac{1}{\left(c-a\right)\left(c-b\right)}\)

\(=\frac{1}{\left(a-b\right)\left(a-c\right)}-\frac{1}{\left(b-c\right)\left(a-b\right)}+\frac{1}{\left(a-c\right)\left(b-c\right)}\)

\(=\frac{b-c-a+c+a-b}{\left(a-b\right)\left(a-c\right)\left(b-c\right)}=0\)

Answer 2

(a - b)(a - c) + 1

= a(b - c) + 1

(b - c)(b - a) + 1

= b(c - a) + 1

(c - a)(c - b)

= c(a - b)

học tốt!

Answer 3

1/(a-b)(a-c) + 1/(b-c)(b-a) + 1/(c-a)(c-b)

=(b-c+c-a+a-b)/(a-b)(b-c)(a-c)

= 0

Ra rồi ó kkk