\(\frac{1}{2}+x=\frac{5}{6}\)
\(x=\frac{5}{6}-\frac{1}{2}\)
\(x=\frac{5}{6}-\frac{3}{6}\)
\(x=\frac{2}{6}\)
\(x=\frac{1}{3}\)
\(\frac{1}{2}+x=\frac{5}{6}\)
\(x=\frac{5}{6}-\frac{1}{2}\)
\(x=\frac{5}{6}-\frac{3}{6}\)
\(x=\frac{2}{6}\)
\(x=\frac{1}{3}\)
Vậy \(x=\frac{1}{3}\)