\(\left(10-4x\right)+120\div2^3=17\)
\(\left(10-4x\right)+120\div8=17\)
\(\left(10-4x\right)+15=17\)
\(10-4x=17-15\)
\(10-4x=2\)
\(4x=10-2\)
\(4x=8\)
\(x=8\div4\)
\(x=2\)
(10-4x)+120:2^3=17
(10-4x)+120= 17.2^3
(10-4x)+120=17.8
(10-4x)+120=136
10-4x= 136-120
10-4x= 16
4x= 10-16
4x=10+(-16)
4x=-6
x= -6:4
x=-1,5
(10-4x)+120 : 2^3=17
(10-4x)+120 : 8 =17
(10-4x)+120 =17.8
(10-4x)+120 =136
10-4x =136-120
10-4x =16
4x =10-16
4x = -6
x =-6:4
x = -1,5
nhớ tk cho mình vs nha
thank you
