a) |x - 1,7| = 2,3
=> x - 1,7 = 2,3 hoặc x - 1,7 = -2,3
=> x = 4 hoặc x = -0,6
b) |x + 3/4| - 1/3 = 0
=> |x + 3/4| = 1/3
=> x + 3/4 = 1/3 hoặc x + 3/4 = -1/3
=> x = -5/12 hoặc x = -13/12
Chúc e học tốt !
\(a,\left|x-1,7\right|=2,3\)
\(\Rightarrow x-1,7=2,3\text{ hoặc }x-1,7=\left(-2,3\right)\)
\(x=2,3+1,7\) \(x=\left(-2,3\right)+1,7\)
\(x=4\) \(x=\left(-0,6\right)\)
Vậy ...
a, l x - 1,7 l = 2,3
TH1: TH2
x - 1,7 = 2,3 x - 1,7 = -2,3
x = 2,3 + 1,7 x = 1,7 + ( -2,3 )
x = 4 x = -0,6
b, l x + 3/4 l - 1/3 = 0
l x + 3/4 l = 1/3
TH1: TH2:
x + 3/4 = 1/3 x + 3/4 = -1/3
x = 1/3 - 3/4 x = -1/3 - 3/4
x = -5/12 x = -13/12
HOK TỐT!
\(b,\left|x+\frac{3}{4}\right|-\frac{1}{3}=0\)
\(\left|x+\frac{3}{4}\right|=0+\frac{1}{3}\)
\(\left|x+\frac{3}{4}\right|=\frac{1}{3}\)
\(\Rightarrow x+\frac{3}{4}=\frac{1}{3}\text{ hoặc }x+\frac{3}{4}=\left(-\frac{1}{3}\right)\)
\(x=\frac{1}{3}-\frac{3}{4}\) \(x=\left(-\frac{1}{3}\right)-\frac{3}{4}\)
\(x=\frac{4}{12}-\frac{9}{12}\) \(x=\left(-\frac{4}{12}\right)-\frac{9}{12}\)
\(x=-\frac{5}{12}\) \(x=\left(-\frac{13}{12}\right)\)
Vậy ...
