Question

1-2+3-4+5-6+7-8+.............+199-200

Answer 1

 Divide that number sequence into 2, odd & even, since the odd always positive & even always negative 
odd number : Un = 2n -1 
even numbers : Un = 2n 

odd sigma(n=100) = n(Un+n0)/2 = n(2n-1+1)/2 = n(2n)/2 = n^2 

even sigma(n=100) = n(Un+n0)/2 = n(2n+2)/2 = n(n+1) = n^2 + n 

sigma(n=100) = n^2 - (n^2 + n) = n^2 - n^2 - n = -n = -100