đề ntn phải ko
1-\(\frac{1}{x}-\frac{1}{3}=\frac{1}{6}\)
\(=>1-\frac{1}{x}=\frac{1}{6}+\frac{1}{3}\)
\(=>1-\frac{1}{x}=\frac{1}{2}\)
\(=>-\frac{1}{x}=1-\frac{1}{2}\)
\(-\frac{1}{x}=\frac{1}{2}\)
\(=>x=-2\)
1-1/x-1/3=1/6
1-1/x=1/6+1/3
1-1/x=3/6
1/x=1-3/6
1/x=3/6
1/x=1/2
<=>x=2