Câu trả lời:
Al + 3HCl -> AlCl3 + \(\dfrac{3}{2}\)H2
Mg + 2HCl -> MgCl2 + H2
Gọi x,y là mol Al, Mg
=> \(\left\{{}\begin{matrix}27x+24y=9\\\dfrac{3}{2}x+y=\dfrac{10,08}{22,4}\end{matrix}\right.\)=> \(\left\{{}\begin{matrix}x=0,2\\y=0,15\end{matrix}\right.\)=> \(\left\{{}\begin{matrix}\%mAl=\dfrac{0,2.27}{9}=60\%\\\%mMg=100\%-60\%=40\%\end{matrix}\right.\)