\(\frac{x-3}{3}-x-4\) ≥ \(\frac{x-4}{4}\)

\(\frac{x+2}{x-2}-\frac{x-2}{x+2}=\frac{-16}{4-x^2}\)

4(a³ - b³) ≥ (a - b)³ với a≥b

Giải phương trình sau :

\(\frac{2}{x-1}=1+\frac{2x}{x+2}\)

The walls of the house are covered .... a coat of paint

A. with B. in C. by D. under